Python program to check Armstrong number

 

Armstrong number :

              Given a number x, determine whether the given number is Armstrong number or not. A positive integer of n digits is called an Armstrong number of order n (order is number of digits) 

abcd... = pow(a,n) + pow(b,n) + pow(c,n) + pow(d,n) + ....

Example:

Input : 153
Output : Yes
153 is an Armstrong number.
1*1*1 + 5*5*5 + 3*3*3 = 153

Program :

def power(x, y):

     

    if y == 0:

        return 1

    if y % 2 == 0:

        return power(x, y // 2) * power(x, y // 2)

         

    return x * power(x, y // 2) * power(x, y // 2)

 

# Function to calculate order of the number

def order(x):

 

    # Variable to store of the number

    n = 0

    while (x != 0):

        n = n + 1

        x = x // 10

         

    return n

 

# Function to check whether the given

# number is Armstrong number or not

def isArmstrong(x):

     

    n = order(x)

    temp = x

    sum1 = 0

     

    while (temp != 0):

        r = temp % 10

        sum1 = sum1 + power(r, n)

        temp = temp // 10

 

    # If condition satisfies

    return (sum1 == x)

 

# Driver code

x = 153

print(isArmstrong(x))

 

x = 1253

print(isArmstrong(x))




Output:

True
False